Can anyone explain to me about this modulo stuff? I’ve never studied it before. If you can, I’d also like you to indicate where I can find documents related to this? Thanks in advance.
I did not understand your question, but ok, I think I make mistake. Modulo in here, i mean ចែកដាច់ (មិនដែលដឹងថាគេប្រើពាក្យអីទេ តែខ្ជឹលដូចឃី ចុះឡើងក៏សរសេរចឹងទៅ)។
Too straight Forward….
.
3^2n+7 =9^n+7=1+7=8=0 (mod 8)
a^n – b^n = ? Pleas help, if any formula or not
Ok, even I don’t that formula, but try other complicated way
(3^n)^2 -1 + 8 modulo 8 is true
Should approve (3^n)^2 -1 modulo 8 is true
=> ((3^n) – 1) ((3^n) + 1) modulo 4*2
((3^n) – 1) et ((3^n) + 1) modulo 2 true for all n (pair and impair), bc 3^n is impair (+ or -) 1 is pair => modulo 2 is true
((3^n) – 1) modulo 4 if n is pair bc (3^m)^2 – 1 = ((3^m)-1)((3^m)+1) modulo 2*2 (i)
(3^n) + 1 modulo 4 if n is impair, (3^n) + 1 = (3^(2m+1)) – 3 + 4, => 3( 3^2m -1) + 4, approve 3^2m -1 modulo 4 the same as (i)
Hope you it is true,
not in (i) is true for all m.
want to know this one is correct or not
Can anyone explain to me about this modulo stuff?
I’ve never studied it before. If you can, I’d also like you to indicate where I can find documents related to this? Thanks in advance.
for modulo..it like this
5=1(mod2)
by Fermat little therorem if p is a prime number thus a^p=a(modp)
I did not understand your question, but ok, I think I make mistake. Modulo in here, i mean ចែកដាច់ (មិនដែលដឹងថាគេប្រើពាក្យអីទេ តែខ្ជឹលដូចឃី ចុះឡើងក៏សរសេរចឹងទៅ)។
តាមពិត Modulo មានន័យថាសំណល់ចែក។ “(3^n)^2 -1 + 8 modulo 8 is true” គួរសរសេរ “(3^n)^2 -1 + 8 modulo 8 equal 0 ”
5 modulo 2 = 1
difficult
កំនត់លេខ៦ខ្ទង់ដែលផ្ទៀងផ្ទាត់ពេលគុណនឹង២ ៣ ៤ ៥ រឺ៦គេទទូលបានលេខមានតូលេខដូចលេខដើម(ខុសលំដាប់លំដោយ)